Odpowiedź:
[tex]\begin{cases}x+\frac{1}{2}y=8\ \ /*2\\\frac{1}{2}x-\frac{3}{4}y=-4\ \ /*4\end{cases}\\\\\\\begin{cases}2x+y=16\\2x-3y=-16\ \ /*(-1)\end{cases}\\\\\\+\begin{cases}2x+y=16\\-2x+3y=16\end{cases}\\---------\\4y=32\ \ /:4\\y=8\\\\\\2x+8=16\\\\2x=16-8\\\\2x=8\ \ /:2\\\\x=4\\\\\begin{cases}x=4\\y=8\end{cases}[/tex]
