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[tex]\frac{1}{5}(10a-5b+15)=\frac{1}{5}\cdot10a-\frac{1}{5}\cdot5b+\frac{1}{5}\cdot15=\boxed{2a-b+3}\\\\\frac{8x+4y-10}{2}=\frac{2(4x+2y-5)}{2}=\boxed{4x+2y-5}\\\\3x+4-\frac{15x-12}{3}=3x+4-\frac{3(5x-4)}{3}=3x+4-(5x-4)=3x-4-5x+4=\boxed{-2x+8}[/tex]
