Odpowiedź:
13a)
(x+1)(x+2)(x+3)=
(x^2+2x+x+2)(x+3)=
(x^2+3x+2)(x+3)=
x^3+3x^2+2x+6
b)
(x-2)(x+5)(2x-1)=
(x^2+5x-2x-10)(2x-1)=
(X^2+3x-10)(2x-1)=
2x^3-2x^2+6x^2+10=
2x^3+4x^2+10
c)
(x-4)(x+1)^2=
(x-4) {(x+1)(x+1)}=
(x-4)(x^2+x+x+1)=
(x-4)(x^2+2x+1)=
x^3+2x^2+x-4x^2-8x-4=
x^3-2x^2-7x-4
d)
(2x-3)^2(x+3)=
{(2x-3)(2x-3)}(x+3)=
(4x^2-6x-6x+9)(x+3)=
(4x^2-12x+9)(x+3)=
4x^3+12x^2-12x^2-26x+9x+27=
4x^3-17x+27
Szczegółowe wyjaśnienie:
