Odpowiedź:
zad1
[tex]7a - \frac{1}{2} a = 7 \times 8 - \frac{1}{2} \times 8 = 56 - 4 = 52[/tex]
zad2
[tex]3 {b}^{2} + 2b = 3 \times {( - 4)}^{2} + 2 \times ( - 4) = 3 \times 16 - 8 = 48 - 8 = 40[/tex]
zad3
nie widać liczb
zad4
[tex]2x(y + {1}^{2} ) = 2 \times ( - 4) \times (y + 1) = - 8(y + 1) = - 8y - 8[/tex]
