[tex]dane:\\v_1 = 18\frac{km}{h}\\t = 10 \ s\\v_2 = 108\frac{km}{h}\\szukane:\\a = ?\\\\Rozwiazanie\\\\a = \frac{\Delta v}{t}\\\\\Delta v = v_2 - v_1 = 108\frac{km}{h} - 18\frac{km}{h} = 90\frac{km}{h} = 90\cdot\frac{1000 \ m}{3600 \ s} = 25\frac{m}{s}\\\\a = \frac{25\frac{m}{s}}{10 \ s} = 2,5\frac{m}{s^{2}}[/tex]
Odp. Przyspieszenie tego ciała a = 2,5 m/s².
