Odpowiedź:
[tex]a)\ \ \sqrt{9^2+7^2+3^2+2^2+1^2}=\sqrt{81+49+9+4+1}=\sqrt{144}=12\\\\\\b)\ \ (\sqrt[3]{216}-\sqrt{\sqrt[3]{64}})^3=(6-\sqrt{4})^3=(6-2)^3=4^3=64\\\\\\c)\ \ \frac{-3^4-(-3)^4}{6^3}*\sqrt[3]{2\frac{10}{27}}=\frac{-81-81}{216}*\sqrt[3]{\frac{64}{27}}=\frac{-162}{216}*\frac{4}{3}=-\frac{3}{4}*\frac{4}{3}=-1\\\\\\d)\ \ \sqrt{\dfrac{1^3+2^3+3^3+4^3+5^3}{1^3+2^3+3^3+4^3+5^3+6^3}}=\sqrt{\dfrac{1+8+27+64+125}{1+8+27+64+125+216}}=[/tex]
[tex]=\sqrt{\dfrac{100+125}{100+125+216}}=\sqrt{\dfrac{225}{441}}=\sqrt{\dfrac{25}{49}}=\dfrac{5}{7}[/tex]
