Hej!
f]
[tex]\frac{(x-2)(x+4)}{x^2-4}=0\\\\x^2-4\neq0\\\\(x+2)(x-2)\neq0\rightarrow x\neq-2, \ x\neq2\\\\(x-2)(x+4)=0\\\\x-2=0\rightarrow x=2\notin\mathbb{D}\\\\x+4=0\rightarrow x=-4\in\mathbb{D}[/tex]
Odp. x = -4
g]
[tex]\frac{x^2-1}{x+1}=0\\\\x+1\neq0\rightarrow x\neq-1\\\\x^2-1=0\\\\(x+1)(x-1)=0\\\\x+1=0\rightarrow x=-1\notin\mathbb{D}\\\\x-1=0\rightarrow x=1\in\mathbb{D}[/tex]
Odp. x = 1
h]
[tex]\frac{x(x-2)(x+3)}{x^2-3}=0\\\\x^2-3\neq0\\\\(x+\sqrt3)(x-\sqrt3)\neq0\rightarrow x\neq-\sqrt3, \ x\neq\sqrt3\\\\x(x-2)(x+3)=0\\\\x=0\in\mathbb{D}\\\\x-2=0\rightarrow x=2\in\mathbb{D}\\\\x+3=0\rightarrow x=-3\in\mathbb{D}[/tex]
Odp. x = 0 ∧ x = 2 ∧ x = -3
