Odpowiedź:
e) (x² - 5) : x² - 25 = 0 /× x²-25
x²-5=0
x² = 5
x = √5 v x=-√5
f) [(x-2)(x+4)] : x²-4 = 0 / × x²-4
(x-2)(x+4) = 0
x-2= 0 v x+4=0
x=2 v x=-4
g) (x²-1) : (x+1) = 0 /× x+1
x²-1 = 0
x²=1
x=1 v x=-1
h) [x(x-2)(x+3) : x²-3 = 0 /×x²-3
x(x-2)(x+3) = 0
x = 0 v x-2 =0 v x+3=0
x=0 v x=2 v x=-3
