Odpowiedź:
Szczegółowe wyjaśnienie:
a)
[tex]sin\alpha=\frac{5}{13}\\ cos\alpha=\frac{12}{13}\\ tg\alpha=\frac{5}{12}\\\frac{sin\alpha}{cos\alpha}=tg\alpha\\\frac{\frac{5}{13}}{\frac{12}{13}}=\frac{5}{13}\cdot \frac{13}{12}=\frac{5}{12}=tg\alpha[/tex]
b)
[tex]sin\alpha=\frac{1}{\sqrt{10}}\\cos\alpha=\frac{3}{\sqrt{10}}\\tg\alpha=\frac{1}{3}[/tex]
[tex]\frac{sin\alpha}{cos\alpha}=tg\alpha[/tex]
[tex]\frac{\frac{1}{\sqrt{10} } }{\frac{3}{\sqrt{10} } } =\frac{1}{\sqrt{10} }\cdot \frac{\sqrt{10}}{3}=\frac{1}{3}=tg\alpha[/tex]
