Odpowiedź:
[tex] \frac{ {x}^{2} - 1 }{x + 2} = 0[/tex]
[tex]( {x}^{2} - 1)(x + 2) = 0[/tex]
x²-1=0 v x+2=0
(x+1)(x-1)=0 v x=-2
x=-1 v x=1
[tex] \frac{ {x}^{2} - 5 }{ {x}^{2} - 25} = 0[/tex]
[tex]( {x}^{2} - 5)( {x}^{2} - 25) = 0[/tex]
x²-5=0 v x²-25=0
(x-√5)(x+√5)=0 v (x-5)(x+5)=0
x-√5=0 v x+√5=0 v x-5=0 v x+5=0
x=√5 v x=-√5 v x=5 v x=-5
[tex] \frac{(x - 2)(x + 4)}{ {x}^{2} - 4} = 0[/tex]
[tex](x - 2)(x - 4)( {x}^{2} - 4) = 0 [/tex]
x-2=0 v x-4=0 v x²-4=0
x=2 v x=4 v (x-2)(x+2)=0
x=2 v x=4 v x+2=0
x=-2
