Odpowiedź:
[tex](2\sqrt{3}-\sqrt{2})^{2}+(2\sqrt{3}+\sqrt{2})^{2}=\\\\=(2\sqrt{3})^{2}-2\cdot2\sqrt{3}\cdot\sqrt{2}+(\sqrt{2})^{2}+(2\sqrt{3})^{2}+2\cdot2\sqrt{3}\cdot\sqrt{2}+(\sqrt{2})^{2}=\\\\=12-4\sqrt{6}+2+12+4\sqrt{6}+2 = 28[/tex]
Szczegółowe wyjaśnienie:
[tex](a-b)^{2} = a^{2}-2ab + b^{2}\\\\(a+b)^{2} = a^{2}+2ab+b^{2}[/tex]
