Odpowiedź:
9.
a) [tex]\frac{4}{\sqrt{2} } * \frac{\sqrt{2} }{\sqrt{2}} = \frac{4\sqrt{2}}{2} = 2\sqrt{2}[/tex]
b) [tex]\frac{3}{2\sqrt{2}} * \frac{\sqrt{2}}{\sqrt{2}} = \frac{3\sqrt{2}}{2*2} = \frac{3}{4} \sqrt{2}[/tex]
c) [tex]\frac{4}{\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{4\sqrt{3}}{3}[/tex]
d) [tex]\frac{6}{5\sqrt{3}} * \frac{\sqrt{3}}{\sqrt{3}} = \frac{6\sqrt{3}}{5*3} = \frac{2\sqrt{3}}{5}[/tex]
10.
a)
[tex]P = 3\sqrt{2} * \sqrt{2} = 3 * 2 = 6[cm^{2}]\\L = 2 * 3\sqrt{2} + 2 * \sqrt{2} = 6\sqrt{2} + 2\sqrt{2} = 8\sqrt{2}[cm][/tex]
b)
[tex]P = \sqrt{12} * \sqrt{3} = \sqrt{36} = 6[cm^{2} ]\\L= 2* \sqrt{12} + 2* \sqrt{3}= 2\sqrt{4* 3} + 2\sqrt{3}= 4\sqrt{3} + 2\sqrt{3}= 6\sqrt{3} [cm][/tex]