a)
[tex]\frac{1}{2}x + 6 = \frac{1}{4}x + 2\\\\\frac{1}{2}x - \frac{1}{4}x = 2-6\\\\\frac{2}{4}x - \frac{1}{4}x = -4\\\\\frac{1}{4}x = -4 \ \ |\cdot 4\\\\x = -16[/tex]
b)
[tex]\frac{x+3}{3} = \frac{x-5}{2} \ \ |\cdot6\\\\2(x+3) = 3(x-5)\\\\2x+6 = 3x-15\\\\2x-3x = -15-6\\\\-x = -21 \ \ /:(-1)\\\\x = 21[/tex]
