[tex]\int {x} \, dx = (\frac{1}{2}x^{2}) \\W granicach (0,6) \\ (\frac{1}{2}6^{2})- (\frac{1}{2}0^{2})=18\\\\Regula \\de'Hospitala: \lim_{x \to 2} \frac{x^2-4}{x-2}= \lim_{x \to 2} \frac{2x}{1}=4 \\LUB\\x^{2} -4 = (x+2)(x-2)\\Czyli:\\\lim_{x \to 2} \frac{x^2-4}{x-2}= \lim_{x \to 2} (x+2)=4 \\\\\\3*cos(0)=3[/tex]
