Odpowiedź :
Odpowiedź:
[tex]3(2x-1)+4(1-x)=6x-3+4-4x=2x+1\\\\2(7z+5)-6(x-3)=14z+10-6x+18=14z-6x+28\\\\je\'sli\ \ bedzie\\\\2(7x+5)-6(x-3)=14x+10-6x+18=8x+28\\\\-2x(8-x)-5(x^2+3x)=-16x+2x^2-5x^2-15x=-3x^2-31x\\\\5(3x-2)-3(4x+6)=15x-10-12x-18=3x-28[/tex]
Zadanie
3(2x- 1)+ 4(1- x)= 6x-3+ 4- 4x= 2x+ 1
2(7x +5)- 6(x - 3) = 14x+ 10- 6x+ 18= 8x+ 28
-2x(8- x)- 5(x2+ 3x) = -16x+2x²-5x²- 15x= -3x²- 31x
5(3x- 2)- 3(4x+ 6)= 15x- 10- 12x- 18= 3x- 28