Szczegółowe wyjaśnienie:
[tex]\frac{6t-9}{3} -(-4t+2s-7)=\frac{6t-9}{3}-\frac{(-4t+2s-7)*3}{3} =\\\\=\frac{6t-9}{3}-\frac{(-12t+6s-21)}{3}=\frac{6t-9-(-12t+6s-21)}{3} =\frac{6t-9+12t-6s+21}{3}=\\\\=\frac{18t-6s+12}{3} =\frac{3(6t-2s+4)}{3} =6t-2s+4[/tex]
