Odpowiedź:
Zad.2
[tex]a).(p + 4)(p - 2) = p ^{2} - 2p + 4p \\ - 8 = p ^{2} + 2p - 8[/tex]
[tex]b).(- 3 + a)(a - 4) = - 3a + 12 + a ^{2} - 4a = - 12a + 12 + a^{2} [/tex]
[tex]c).(2x + 5)(x + 3) = 2x^{2} + 6x + 5x + 15 = 2x^{2} + 11x + 15[/tex]
[tex]d).(4m + 1)(2m - 5) = 8m^{2} - 20m + 2m - 5 = 8m^{2} + 22m - 5[/tex]
[tex]e).(5 - p)(4 + 3p) = 20 + 15p \\ - 4p - 3p^{2} = 20 + 11p - 3p^{2} [/tex]
Zad.3
[tex]a).(2p + 3q)(5p + 2q) = 10p^{2} + 4p q + 15pq + 6q^{2} = 16p^{2} q ^{2} + 19pq[/tex]
[tex]b).(3a + 2b)(a - 4b) = 3a^{2} - 12ab + 2ba - 2b^{2} = 3a^{2} - 10ab - 2b^{2} [/tex]
[tex]c).(2x - 3y)(3x - 2y) = 6x^{2} - 4xy - 6yx + 6y^{2} = 6x^{2} - 10xy + 6y^{2} [/tex]
[tex]d).(m + 2n)(5m - 2n) = 5m^{2} - 2mn + 10mn - 4n^{2} = 5m^{2} + 8mn - 4n^{2} [/tex]
[tex]e).(5a^{2} - b)(2b + 3a) = 10a^{2}b + 15a^{3} - 2b^{2} - 3ab[/tex]
Mam nadzieję że pomogłam :)
