Odpowiedź:
zad 1
-x(x-3a+1) = -x2+3a-x
3p(p-2) = 3p2-6p
-4a(-a+5b+6) = 4a2-20ab-24a
5z(-y+x-z) = -5zy+5zx-5z2
-2m(n-m+3) = -2mn+2m2-6m
k(-g-4) = -kg-4k
zad 2
x(x-2)+2