Odpowiedź:
a)
(-12b+4)÷4=-3b+1
b)
[tex](6 {x}^{2} + x - 1) \div ( - \frac{5x + 10y}{5} ) = (6 {x}^{2} + x - 1) \times ( - \frac{5}{5x + 10y}) = \frac{ -30 {x}^{2} }{5x + 10y} + \frac{ - 5x}{5x + 10y} + \frac{5}{5x + 10y} [/tex]
d)
(-10b+4)÷2=-5b+2
e)
(-12x²+x-1)÷(?)
