Hej!
Zadanie 1 :
dam w załączniku za chwilę
Zadanie 2 :
[tex]a] \ 1,2\cdot0,03=\frac{12}{10}\cdot\frac{3}{100}=\frac{\not6^3}{5}\cdot\frac{3}{\not100_{50}}=\frac{9}{250}\\\\b] \ \frac{3}{4}\cdot\frac{12}{13}=3\cdot\frac{3}{13}=\frac{9}{13}\\\\c] \ 1\frac{2}{5}\cdot\frac{5}{8}=\frac{7}{5}\cdot\frac{5}{8}=\frac{7}{8}\\\\d] \ -8\cdot(-9)=72\\\\e] \ 0,25\cdot(-\frac{1}{5})=\frac{1}{4}\cdot(-\frac{1}{5})=-\frac{1}{20}[/tex]
Pozdrawiam! - Julka
