Odpowiedź:
zad1
-2x+(-6xy+4x-y)=-2x-6xy+4x-y=2x-y-6xy
k-(-2k+8m-3km)=k+2k-8m+3km=3k-8m+3km
-6xy-(2xy-3x+4y)=-6xy-2xy+3x-4y=-8xy+3x-4y
9a+4c-(8c-2a)=9a+4c-8c+2a=11a-4c
-(-3t+w)-(t-2w)=3t-w-t+2w=2t+w
-(3x+1)+(6x+2)=-3x-1+6x+2=3x+1
zad2
(4pr-p+3)+(-pr-p-8)=4pr-p+3-pr-p-8=3pr-2p-5
-(5xy-x+8)+(6-3x+xy)=-5xy+x-8+6-3x+xy=-4xy-2x-2
2a+3b-4c+5d-(a-7b+2c-6d)=2a+3b-4c+5d-a+7b-2c+6d=a+10b-6c+11d
-(x²+x+1)-(-x²+x-1)+(-x²-x-1)=-x²-x-1+x²-x+1-x²-x-1=-x²-3x-1
Szczegółowe wyjaśnienie:
