7. Ile wynosi obwód trapezu o wierzchołkach A=(-2,3), B=(-2,5), C=(-6,-2), D=(-6,5)? *
(1 punkt)​



Odpowiedź :

[tex] |AB| = \sqrt{( - 2 + 2 {)}^{2} + (5 - 3 {)}^{2} } = \sqrt{0 + {2}^{2} } = \sqrt{4} = 2[/tex]

[tex] |BC| = \sqrt{( - 6 + 2 {)}^{2} + ( - 2 - 5 {)}^{2} } = \sqrt{( - 4 {)}^{2} + {( - 7)}^{2} } = \sqrt{16 + 49} = \sqrt{65} [/tex]

[tex] |CD| = \sqrt{( - 6 + 6 {)}^{2} + (5 + 2 {)}^{2} } = \sqrt{0 + {7}^{2} } = \sqrt{49} = 7[/tex]

[tex] |AD| = \sqrt{( - 6 + 2 {)}^{2} + (5 - 3 {)}^{2} } = \sqrt{( - 4 {)}^{2} + {2}^{2} } = \sqrt{16 + 4} = \sqrt{20} [/tex]

[tex]2 + \sqrt{65} + 7 + \sqrt{20} = 9 + \sqrt{65} + 2 \sqrt{5} [/tex]

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