Odpowiedź :
a)
[tex]x^2+4x=0\\x(x+4)=0\\x=0 \vee x=-4[/tex]
b)
[tex]x^2-9=0\\x^2=9\\x=-3 \vee x=3[/tex]
c)
[tex]2x^2-3x+1=0\\2x^2-2x-x+1=0\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\x=\dfrac{1}{2} \vee x=1[/tex]
a)
[tex]x^2+4x=0\\x(x+4)=0\\x=0 \vee x=-4[/tex]
b)
[tex]x^2-9=0\\x^2=9\\x=-3 \vee x=3[/tex]
c)
[tex]2x^2-3x+1=0\\2x^2-2x-x+1=0\\2x(x-1)-1(x-1)=0\\(2x-1)(x-1)=0\\x=\dfrac{1}{2} \vee x=1[/tex]