Odpowiedź:
[tex]wzor \: pole \: trojkata \: to \: \frac{1}{2} + \times a \times h[/tex]
[tex]a) \frac{1}{2} \times 7 \times 4 = 14 {cm}^{2} [/tex]
[tex]b) \frac{1}{2} \times 6 \times 8 = 24 {cm}^{2} [/tex]
[tex]c) \frac{1}{2} \times 6 \times 9 = 27 {cm}^{2} [/tex]
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