a) M CuO = 80
m Cu = 64
m O = 16
80 - 100%
64 - x
x = 64*100/80 = 80% 100-80=20%
Procent Cu = 80%, procent O = 20%
b) M AlCl3 = 133,5
m Cl = 35,5 * 3 = 106,6
m Al = 27
133,5 - 100%
106,5 - x
x= 106,5*100/133,5 = 79,8%
Procent Cl = 79,8%, procent Al = 20,2%
c) M BaBr2 = 297
m Ba = 137
m Br = 80 * 4 =160
297 - 100%
137 - x
x=137*100/297 = 46,1% 100-46,1= 53,9%
Procent Ba = 46,1%, procent Br = 53,9%.
