Odpowiedź :
1)
[tex] \frac{x + 5}{10} + \frac{2x + 5}{2} = \frac{2 - x}{5} \\ x + 5 + 5(2x + 5) = 2(2 - x) \\ x + 5 + 10x + 25 = 4 - 2x \\ 11x + 30 = 4 - 2x \\ 13x = - 26 \\ x = - 2[/tex]
2)
[tex] \frac{x + 4}{5} + \frac{2x + 9}{10} = \frac{ - 2 - x}{2} \\ 2 (x +4) + 2x + 9 = 5( - 2 - x)\\ 2x + 8 + 2x + 9 = - 10 - 5x \\ 4x + 17 = - 10 - 5x \\ 9x = - 27 \\ x = - 3[/tex]
3)
[tex] \frac{2y + 4}{4} = \frac{1}{2} y + 1 \\ 2y + 4 = 2y + 4 \\ 0 = 0[/tex]
4)
[tex] \frac{x - 1}{3} - \frac{x - 2}{2} = \frac{2x - 5}{6} \\ 2(x - 1) - 3(x - 2) = 2x - 5 \\ 2x - 2 - 3x + 6 = 2x - 5 \\ - x + 4 = 2x - 5 \\ - 3x = - 9 \\ x = 3[/tex]
5)
[tex] \frac{x - 1}{2} + \frac{1}{4} = \frac{2x + 1}{4} - \frac{x + 1}{2} \\ 2(x - 1) + 1 = 2x + 1 - 2(x + 1) \\ 2x - 2 + 1 = 2x + 1 - 2x - 2 \\ 2x - 1 = - 1 \\ 2x = 0 \\ x = 0[/tex]