Odpowiedź:
[tex](\frac{3}{4} - \frac{1}{3} )*4\frac{4}{5} = \frac{5}{12}* \frac{24}{5} = 2[/tex]
[tex]8*1\frac{3}{8}-(1\frac{2}{3})^{2} = 8*\frac{11}{8} -(\frac{5}{3})^{2} = 11-\frac{25}{9}= \frac{74}{9} = 8\frac{2}{9}[/tex]
[tex]1\frac{1}{2}*(3\frac{1}{4}-1\frac{5}{12})+(\frac{3}{2})^{3} = \frac{3}{2} * (\frac{13}{4}-\frac{17}{12} )+\frac{27}{8} =\frac{3}{2}*\frac{11}{6}+\frac{27}{8} = \frac{1}{2}*\frac{11}{2} +\frac{27}{8}= \frac{11}{4}+\frac{27}{8} = \frac{49}{8} = 6\frac{1}{8}[/tex]
