Odpowiedź :
[tex]dane:\\F = 30 \ N\\m = 5 \ kg\\szukane:\\a = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m}\\\\a = \frac{30 \ N}{5 \ kg} = 6\frac{N}{kg} = 6\frac{m}{s^{2}}[/tex]
[tex]Odp. \ B.[/tex]
[tex]dane:\\F = 30 \ N\\m = 5 \ kg\\szukane:\\a = ?\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F}{m}\\\\a = \frac{30 \ N}{5 \ kg} = 6\frac{N}{kg} = 6\frac{m}{s^{2}}[/tex]
[tex]Odp. \ B.[/tex]