Odpowiedź:
H3SO4=3u+32u +64u=98u
CaS= 40u +32u =74u
2 MgO= 2 *( 24u +16u) = 80u
3H2O= 3* (2u + 16u) =54u
4 Na2O= 4*(46u +16u)= 248u
5K2S= 5*(78u +32u) = 550u
3NaOH= 5*(23u +16u +1u) = 200u
7 CO2= 7* (12u +32u) = 308u
10 MgSO4= 10*(24u +64u)= 880u
5SO3= 5*(32u +48u)= 400u
3N2O5 = 3*( 28u +80u) =324u
4HF =2*( 4u + 19u) = 92u
5PbO =5*( 207u +16u) = 11115u
2H2CO3 =2* (2u+12u + 48u) =124u
