[tex]Zadanie\\\\e)\\\\-3\frac{1}{2}-(-1\frac{5}{8})=-3\frac{4}{8}+1\frac{5}{8}=-2\frac{12}{8}+ 1\frac{5}{8}=-1\frac{7}{8}\\\\f)\\\\-11,5-(-1\frac{7}{8})=-11\frac{1}{2}+ 1\frac{7}{8}=-11\frac{4}{8} +1\frac{7}{8}=-10\frac{12}{8}+1\frac{7}{8}= -9\frac{5}{8}\\\\g)\\\\-8,5-(-2\frac{2}{3})= -8\frac{1}{2}+2\frac{2}{3}= -8\frac{3}{6}+2\frac{4}{6}= -7\frac{9}{6}+2\frac{4}{6}= -5\frac{5}{6}[/tex]
