Odpowiedź:
1. Sześcian ma 12 krawędzi.
36 : 12 => a = 3 dm
V = Pp × h
V = (3 × 3) × 3 = 9 × 3 = 27 dm³
2. V = [tex]\frac{1}{3}[/tex]Pp × h
Pp = 2 × 2 = 4 cm²
V = [tex]\frac{1}{3}[/tex] × 4 × 15 = [tex]\frac{60}{3}[/tex] = 20 cm³
3. a = 6, h =3
Pp = [tex]\frac{a^{2}\sqrt{3} }{4}[/tex] = [tex]\frac{36\sqrt{3} }{4}[/tex] = 9[tex]\sqrt{3}[/tex]
Pc = Pole powierzchni bocznej + 2Pp
Ppb = 3 × (6 × 3) = 3 × 18 = 54
Pc = 54 + 2 × 9[tex]\sqrt{3}[/tex] = 54 + 18[tex]\sqrt{3}[/tex]
V = Pp × h = 9[tex]\sqrt{3}[/tex] × 3 = 27[tex]\sqrt{3}[/tex]