Odpowiedź :
Odpowiedź:
a) (3*(-2)+2)(5*(-2)-8)=-4*(-18)=72
b) ((-3)^2+2(-3+3))/((-3)^2-2)=11/7
a) x = -2, y = 2
(3x + y)(5x - 8) = (3*(-2) + 2)(5*(-2) - 8) = (-6 + 2)(-10 - 8) = (-4)*(-18) = 72
b) x = -3
[tex]\frac{x^{2} + 2(x+3)}{x^{2} - 2} = \frac{(-3)^{2} +2(-3+3)}{(-3)^{2} - 2} = \frac{9+2*0}{9-2} = \frac{9}{7} = 1\frac{2}{7}[/tex]