Odpowiedź :
a) mCuO= 64+16=80 (u)
b) mHCl= 1+35,5=36,5 (u)
c) mH2SO4=2*1+32+16*4=98 (u)
d) mK2O=39*2+16=54 (u)
e) NaOH=23+16+1=40 (u)
f) mH2S=1*2+32=34 (u)
a) mCuO = 64 + 16 = 80 (u)
b) mHCl = 1 + 35,5 = 36,5 (u)
c) MH2SO4 = 2 * 1 + 32 + 16 * 4 = 98 (u)
d) mK20 = 39 * 2 + 16 = 54 (u)
e) NaOH = 23 + 16 + 1 = 40 (u) f) mH2S = 1 * 2 + 32 = 34 (u)
b) mHCl = 1 + 35,5 = 36,5 (u)
c) MH2SO4 = 2 * 1 + 32 + 16 * 4 = 98 (u)
d) mK20 = 39 * 2 + 16 = 54 (u)
e) NaOH = 23 + 16 + 1 = 40 (u) f) mH2S = 1 * 2 + 32 = 34 (u)