Odpowiedź:
Szczegółowe wyjaśnienie:
Czemu to takie małe ?
a) x(x²-16) = 0
x(x-4)(x+4) = 0
x1 = 0
x2 = 4
x3 = -4
b) x(x² + 16)=0
x1 = 0 i tyle !
c) x(4x²+1) = 0
to samo
x = 0
d) x(x²+2x+1) = 0
x1=0
Δ = 4-4 = 0
x2 = x3 = -2/2 = -1
e) x(x²-4x+4) = 0
Δ = 16 - 16 = 0
x2 = x3 = 4/2 = 2
f) x(4x² -4x + 1) = 0
x2 = x3 = 4/8 = 1/2
