[tex]Zadanie\\\\a=8\ cm\\b=17\ cm\\h=?\\\\(\frac{1}{2}a)^{2}+h^{2}=b^{2}\\\\4^{2}+h^{2}= 17^{2}\\\\h^{2}+16=289\ \ \ \mid-16\\\\h^{2}=273\\\\h=\sqrt{273}\ cm\\\\P=\frac{1}{2}\cdot a\cdot h\\\\ P=\frac{1}{2}\cdot8\cdot\sqrt{273}=(4\sqrt{273})\ cm^{2}[/tex]
