1.
[tex]dane:\\F_{w} = 1,5 \ kN = 1,5\cdot1000 \ N = 1500 \ N\\m = 250 \ g = 0,25 \ kg\\szukane:\\a = ?\\\\Rozwiazanie\\\\Z \ II \ zasady \ dynamiki\\\\a = \frac{F_{w}}{m}\\\\a = \frac{1500 \ N}{0,25 \ kg}\\\\a = 6000\frac{N}{kg} = 6000\frac{m}{s^{2}}[/tex]
2.
[tex]dane:\\m = 0,5 \ dag =0,005 \ kg\\a = 1,5\frac{m}{s^{2}} = 1,5\frac{N}{kg}\\szukane:\\F = ?\\\\Rozwiazanie\\\\a = \frac{F}{m} \ \ /\cdot m\\\\F = m\cdot a\\\\F = 0,005 \ kg\cdot1,5\frac{N}{kg}\\\\F = 0,0075 \ N[/tex]