Odpowiedź:
[tex]\left \{ {{9x-2y=5} \atop {4x+y=-1}} \right. \\\left \{ {{9x-2y=5} \atop {8x+2y=-2}} \right. \\\\17x=3\\x=\frac{3}{17} \\y=-1-4x\\y = -1 - 4 * \frac{3}{17} = - \frac{29}{17}[/tex]
2 równanie
[tex]\left \{ {{3(x+1)+y = 4} \atop {2(x+1)-4y=-2}} \right. \\\left \{ {{12(x+1) + 4y =16} \atop {2(x+1) - 4y=-2}} \right. \\\\14(x+1)=14\\x+1=1\\x= 0\\y = 4 - 3(x+1)\\y = 1[/tex]
