Odpowiedź :
[tex] \frac{4x + 3}{2} = \frac{3x + 1}{3} | \times 6 \\ 3(4x + 3) = 2(3x + 1) \\ 12x + 9 = 6x + 2 \\ 6x = 2 - 9 \\ 6x = - 7 | \div 6 \\ x = - \frac{7}{6} \\ x = - 1 \frac{1}{6} [/tex]
[tex] \frac{4x + 3}{2} = \frac{3x + 1}{3} | \times 6 \\ 3(4x + 3) = 2(3x + 1) \\ 12x + 9 = 6x + 2 \\ 6x = 2 - 9 \\ 6x = - 7 | \div 6 \\ x = - \frac{7}{6} \\ x = - 1 \frac{1}{6} [/tex]