[tex]Zadanie\\\\a=4\ cm\\\\H=45\ mm=4,5\ cm\\\\P_p=6\cdot\frac{a^{2}\sqrt{3} }{4} \\\\P_p= 6\cdot\frac{4^{2}\cdot\sqrt{3} }{4}=6\cdot\frac{16\cdot\sqrt{3} }{4}= 6\cdot4\sqrt{3}= 24\sqrt{3}\ cm^{2} \\\\V=P_p\cdot H\\\\V= 24\sqrt{3}\cdot4,5 =108\sqrt{3}\ cm^{3}\\\\Odp.\ "4"[/tex]
