Odpowiedź :
Rozwiązanie:
Dane:
[tex]m=1500kg\\t=0,75 min=45s\\\Delta v=90\frac{km}{h}=25\frac{m}{s}[/tex]
Szukane:
[tex]F_{w}=?[/tex]
Wzór:
[tex]F=am\\a=\frac{\Delta v}{\Delta t} \\F=\frac{\Delta vm}{\Delta t}[/tex]
Obliczenia:
[tex]F_{w}=\frac{25*1500}{45}=833,34N[/tex]
[tex]dane:\\m = 1500 \ kg\\t = 0,75 \ min = 0,75\cdot60 \ s = 45 \ s\\\Delta v = 90\frac{km}{h} = 90\cdot\frac{1000 \ m}{3600 \ s} = 25\frac{m}{s}\\szukane:\\F_{w} = ?\\\\Rozwiazanie\\\\a = \frac{F_{w}}{m} \ \ /\cdot m\\\\F_{w} = m\cdot a\\\\a = \frac{\Delta v}{t} = \frac{25\frac{m}{s}}{45 \ s} = \frac{5}{9} \ \frac{m}{s^{2}} = 0,(5)\frac{m}{s^{2}}\\\\F_{w} = 1500 \ kg\cdot\frac{5}{9}\frac{m}{s^{2}}\\\\F_{w} = 833,(3) \ N\approx833,3 \ N[/tex]