[tex]dane:\\P = 200 \ W\\I = 100 \ mA = 0,1 \ A\\t = 2 \ min = 120 \ s\\szukane:\\a) \ U = ?\\b) \ W = ?\\\\Rozwiazanie\\\\a)\\\\P = U\cdot I \ \ /:I\\\\U = \frac{P}{I}\\\\U = \frac{200 \ W}{0,1 \ A}\\\\U = 2 \ 000 \ V = 2 \ kV\\\\b)\\\\W = U\cdot I\cdot t\\\\P = U\cdot I, \ zatem\\\\W = P\cdot t\\\\W = 200 \ W\cdot \ 120 \ s\\\\W = 24 \ 000 \ J = 24 \ kJ[/tex]
