Odpowiedź:
zad 1
a)[tex]2^{3}=2*2*2=8[/tex]
[tex]b)6^{2}=6*6=36[/tex]
[tex]c)(-4)^{2}=(-4)*(-4)=16[/tex]
[tex]d)(-2)^{3}=(-2)*(-2)*(-2)=-8[/tex]
[tex]e)(\frac{1}{3})^{3}=\frac{1}{3}*\frac{1}{3}*\frac{1}{3}=\frac{1}{27}[/tex]
[tex]f)(\frac{2}{5})^{4}=\frac{2}{5}*\frac{2}{5}*\frac{2}{5}*\frac{2}{5}=\frac{16}{625}[/tex]
[tex]g)(\frac{5}{4})^{2}=\frac{25}{16}[/tex]
[tex]h)(-\frac{3}{7})^{2}=(-\frac{3}{7})*(-\frac{3}{7})=\frac{9}{49}[/tex]
[tex]i)(-\frac{2}{10})^{3}=(-\frac{2}{10})*(-\frac{2}{10})*(-\frac{2}{10})=-\frac{8}{1000}=-\frac{1}{125}[/tex]
zad 2
[tex]a)(1\frac{1}{4})^{3}=(\frac{5}{4})^{3}=\frac{125}{64}=1\frac{61}{64}[/tex]
[tex]b)(2\frac{2}{3})^{2}=(\frac{8}{3})^{2}=\frac{8}{3}*\frac{8}{3}=\frac{64}{9}=7\frac{1}{9}[/tex]
[tex]c)(-1\frac{1}{2})^{3}=(-\frac{3}{2})^{3}=(-\frac{3}{2})*(-\frac{3}{2})*(-\frac{3}{2})=(-\frac{27}{8})=-3\frac{3}{8}[/tex]
[tex]d)(-2\frac{2}{5})^{2}=(-\frac{12}{5})^{2}=(-\frac{12}{5})*(-\frac{12}{5})=\frac{144}{25}=5\frac{19}{25}[/tex]
Szczegółowe wyjaśnienie:
