Odpowiedź:
[tex]x^2-4x+3\geq 0\\x^2-x-3x+3 \geq 0\\x(x-1)-3(x-1)\geq 0\\(x-1)(x-3) \geq 0\\\\\left \{ {{x\geq 1} \atop {x\geq 3}} \right. \\\left \{ {{x\leq 1} \atop {x\leq 3}} \right. \\\\[/tex]
x ∈ (-∞,1} ∪ {3, +∞)
Zad 2:
[tex]-x^2 +5x +6 \geq 0\\-x^ +6x -x +6 \geq 0\\-x(x-6)-(x-6)\geq 0\\-(x-6)(x-1) \geq 0\\\\\left \{ {{x\leq6} \atop {x\geq -1}} \right. \\\left \{ {{x\geq 6} \atop {x\leq -1}} \right.[/tex]
x∈ {-1,6}
