plus zad 9 i 10 potrzebuje pomocy
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![Plus Zad 9 I 10 Potrzebuje Pomocy class=](https://pl-static.z-dn.net/files/dfb/82ef0dbb58905b8cbef8c8f1f8bf9a7a.jpg)
Zad9
a. 1/3(9a-12b+6)=1/3•3(3a-4b+2)=
=3a-4b+2
b. 5x-10y+25/5=5(x-2y+5)/5=
=x-2y+5
c. 2x+4-(12x-20)/4=2x+4-4(3x-5)/4=
=2x+4-3x+5=-x+9
Zad10
(2x-3)(2x+1)-(2x-1)(2x-4)-6x=
4x²+2x-6x-3-(4x²-8x-2x+4)-6x=
4x²-4x-3-4x²+10x-4-6x= -7 < 0 dla kazdego x∈R.
Liczę na naj :)