(4/9)^1'5=(4/9)^3/2=4/9^3=√4/9^3=(2/3)^3=8/27
[tex]( \binom{4}{9} {}^{2.5} ) {}^{0.6} = ( \frac{4}{9} ) {}^{1.5} = ( \frac{4}{9} ) {}^{ \frac{3}{2} } = \sqrt{( \frac{4}{9}) } {}^{3} = ( \frac{2}{3} ) {}^{3} = \frac{8}{27} [/tex]
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