Odpowiedź:
[tex]1.\\\sqrt{6} = \sqrt{2} *\sqrt{3}\\\\2.\\\sqrt{7} < \sqrt{5} +\sqrt{2} \\(\sqrt{7} = 2,64,\sqrt{5} +\sqrt{2} = 3,65)\\\\3.\sqrt[3]{2} < \sqrt{2} \\\\4. -\sqrt[3]{25} < \sqrt[3]{23}[/tex]
