Odpowiedź:
a = 8, h = 7
Ppc = 2PolePodstawy + Pole powierzchni bocznej
Pp = [tex]\frac{a^{2} \sqrt{3} }{4}[/tex] = [tex]\frac{64\sqrt{3} }{4}[/tex] = 16[tex]\sqrt{3}[/tex]
Ppb = 4 × (7 × 8) = 4 × 56 = 224
Ppc = 2 × 16[tex]\sqrt{3}[/tex] + 224 = 32[tex]\sqrt{3}[/tex] + 224 = 32([tex]\sqrt{3}[/tex] + 7)
V = Pp × h = 16[tex]\sqrt{3}[/tex] × 7 = 112[tex]\sqrt{3}[/tex]