[tex]dane:\\h = 2 \ m\\d = 700\frac{kg}{m^{3}}\\g = 10\frac{N}{kg}\\szukane:\\p = ?\\\\Rozwiazanie\\\\p = d\cdot g\cdot h\\\\p = 700\frac{kg}{m^{3}}\cdot10\frac{N}{kg}\cdot2 \ m\\\\p = 14 \ 000 \ Pa = 14 \ kPa\\\\(1 \kPa = 1000 \ Pa)[/tex]
Odp. Ciśnienie hydrostatyczne p = 14 kPa.
