Rozwiązanie:
Jest to typowe zadanie z tzw. bilansu cieplnego.
Dane:
[tex]m_{1}=1kg\\T_{1}=10 C\\m_{2}=0,5kg\\T_{k}=25C\\c_{w}=4200\frac{J}{kg*K}[/tex]
Szukane:
[tex]T_{2}=?[/tex]
Wzór:
[tex]Q_{pob}=Q_{od}\\m_{1}c_{w}(T_{k}-T_{1})=m_{2}c_{w}(T_{2}-T_{k})\\m_{1}(T_{k}-T_{1})=m_{2}T_{2}-m_{2}T_{k}\\m_{2}T_{2}=m_{1}(T_{k}-T_{1})+m_{2}T_{k}\\T_{2}=\frac{m_{1}(T_{k}-T_{1})+m_{2}T_{k}}{m_{2}}[/tex]
Obliczenia:
[tex]T_{2}=\frac{1(25-10)+0,5*25}{0,5}=\frac{15+12,5}{0,5}=27,5*2=55C[/tex]
