Odpowiedź:
[tex]\begin{cases}4x+3y+3=0\\\frac{x+y}{2}-\frac{x-y}{6}=1\ \ /*6\end{cases}\\\\\\\begin{cases}4x+3y=-3\\3(x+y)-(x-y)=6\end{cases}\\\\\\\begin{cases}4x+3y=-3\\3x+3y-x+y=6\end{cases}\\\\\\\begin{cases}4x+3y=-3\\2x+4y=6\ \ /:2\end{cases}\\\\\\\begin{cases}4x+3y=-3\\x+2y=3\end{cases}\\\\\\\begin{cases}4x+3y=-3\\x=3-2y\end{cases}\\\\\\4(3-2y)+3y=-3\\\\12-8y+3y=-3\\\\-5y=-3-12\\\\-5y=-15\ \ /:(-5)\\\\y=3\\\\\\x=3-2*3=3-6=-3[/tex]
[tex]\begin{cases}x=-3\\y=3\end{cases}[/tex]
